Question

question 1
what are the boundaries of the class 1.87–3.43 ?
a. 1.879 - 3.439
b. 1.87 - 3.43
c. 1.82 - 3.48
d. 1.865 - 3.435

Explanation:

Step1: Determine the precision of the class limits

The class limits are given to two decimal places (1.87 and 3.43), so the precision is 0.01. The boundary of a class is found by subtracting half of the precision from the lower class limit and adding half of the precision to the upper class limit.
Half of the precision ($0.01$) is $\frac{0.01}{2} = 0.005$.

Step2: Calculate the lower boundary

Subtract $0.005$ from the lower class limit ($1.87$):
$1.87 - 0.005 = 1.865$

Step3: Calculate the upper boundary

Add $0.005$ to the upper class limit ($3.43$):
$3.43 + 0.005 = 3.435$

Answer:

d. 1.865 - 3.435