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Question
question 4 of 8
what is the product of $-\frac{1}{3} \cdot \frac{2}{4}$?
\\(\circ\\) $-\frac{6}{1}$
\\(\circ\\) $-\frac{1}{6}$
\\(\circ\\) $\frac{6}{1}$
\\(\circ\\) $\frac{1}{6}$
Step1: Multiply numerators and denominators
To find the product of two fractions, we multiply the numerators together and the denominators together. For \(-\frac{1}{3} \cdot \frac{2}{4}\), the numerators are \(-1\) and \(2\), and the denominators are \(3\) and \(4\). So we have \(\frac{-1 \times 2}{3 \times 4}\).
Step2: Simplify the fraction
First, calculate the numerator: \(-1\times2 = -2\). Then calculate the denominator: \(3\times4 = 12\). So the fraction becomes \(\frac{-2}{12}\). We can simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is \(2\). Dividing \(-2\) by \(2\) gives \(-1\), and dividing \(12\) by \(2\) gives \(6\). So \(\frac{-2}{12}=\frac{-1}{6}\).
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\(-\frac{1}{6}\) (corresponding to the option: \(-\frac{1}{6}\))