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Question
question
what is the product of 10 and $6\sqrt{96}$ in simplest radical form?
Step1: Multiply the coefficients
$10 \times 6\sqrt{96} = 60\sqrt{96}$
Step2: Simplify the radical
Factor 96 into perfect square and remaining factor: $\sqrt{96} = \sqrt{16 \times 6} = \sqrt{16} \times \sqrt{6} = 4\sqrt{6}$
Step3: Multiply with coefficient
$60 \times 4\sqrt{6} = 240\sqrt{6}$
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$240\sqrt{6}$