Question

question what is the volume of a hemisphere with a radius of 42.1 ft, rounded to the nearest tenth of a cubic foot? answer attempt 1 out of 2 ft³ submit answer show examples

Explanation:

Step1: Recall volume formula for hemisphere

The volume formula for a hemisphere is $V=\frac{2}{3}\pi r^{3}$, where $r$ is the radius.

Step2: Substitute the given radius

Given $r = 42.1$ ft, we substitute it into the formula: $V=\frac{2}{3}\pi(42.1)^{3}$.
First, calculate $(42.1)^{3}=42.1\times42.1\times42.1 = 74618.461$.
Then, $V=\frac{2}{3}\pi\times74618.461$.
$\frac{2}{3}\times74618.461\approx49745.64067$.
$V = 49745.64067\pi$.
Using $\pi\approx3.14159$, we have $V\approx49745.64067\times3.14159$.
$V\approx156217.7$.

Answer:

$156217.7$