Question

question what is the volume of a sphere with a radius of 9.2 cm, rounded to the nearest tenth of a cubic centimeter? answer attempt 2 out of 2

Explanation:

Step1: Recall volume formula

The volume formula for a sphere is $V = \frac{4}{3}\pi r^{3}$, where $r$ is the radius.

Step2: Substitute radius value

Given $r = 9.2$ cm, we substitute it into the formula: $V=\frac{4}{3}\pi(9.2)^{3}$.
First, calculate $(9.2)^{3}=9.2\times9.2\times9.2 = 778.688$.
Then, $V=\frac{4}{3}\pi\times778.688$.
$\frac{4}{3}\times778.688\approx1038.251$.
So, $V = 1038.251\pi$.
Using $\pi\approx3.14159$, $V\approx1038.251\times3.14159\approx 3263.8$.

Step3: Round the result

Rounding $3263.8$ to the nearest tenth gives $3263.8$ $cm^{3}$.

Answer:

$3263.8$