Question

question
write the exponential equation as a logarithmic equation.
$6^{\frac{3}{2}} = \sqrt{216}$

Explanation:

Step1: Recall exponent-logarithm relation

For $b^y = x$, $\log_b x = y$

Step2: Match values to the formula

Here $b=6$, $y=\frac{3}{2}$, $x=\sqrt{216}$

Step3: Substitute into logarithmic form

$\log_{6} \sqrt{216} = \frac{3}{2}$

Answer:

$\log_{6} \sqrt{216} = \frac{3}{2}$