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7. équilibre les réactions suivantes: a) \\( \\ce{c7h_{12}(l) + o_{2}(g…

Question

  1. équilibre les réactions suivantes:

a) \\( \ce{c7h_{12}(l) + o_{2}(g) -> co_{2}(g) + h_{2}o(g)} \\)
b) \\( \ce{naoh(aq) + cucl_{2}(aq) -> nacl(aq) + cu(oh)_{2}(s)} \\)
c) \\( \ce{alf_{3}(aq) + li_{2}so_{4}(aq) -> lif(aq) + al_{2}(so_{4})_{3}(s)} \\)
d) \\( \ce{c_{4}h_{8}(l) + o_{2}(g) -> co_{2}(g) + h_{2}o(g)} \\)

  1. trace la structure des molécules organiques suivantes à partir de leurs noms uicpa.

a) hex-3-yne
b) 2,4-diméthyl-4-éthylheptane
c) 3-éthyl-4-propyloctane
d) but-2-ène
e) cyclopropane
f) cyclopentène

Explanation:

Response
For Question 7 (Balancing Chemical Reactions)

Step1: Balance C then H then O

For reaction a): $C_7H_{12}(l) + O_2(g)
ightarrow CO_2(g) + H_2O(g)$

  1. Balance C: $C_7H_{12} + O_2

ightarrow 7CO_2 + H_2O$

  1. Balance H: $C_7H_{12} + O_2

ightarrow 7CO_2 + 6H_2O$

  1. Balance O: Total O on right = $14 + 6 = 20$, so $O_2$ coefficient = 10

Final: $C_7H_{12}(l) + 10O_2(g)
ightarrow 7CO_2(g) + 6H_2O(g)$

Step2: Balance Cu, Cl, Na, OH

For reaction b): $NaOH(aq) + CuCl_2(aq)
ightarrow NaCl(aq) + Cu(OH)_2(s)$

  1. Balance Cu: $NaOH + CuCl_2

ightarrow NaCl + Cu(OH)_2$

  1. Balance OH: Add 2 to NaOH: $2NaOH + CuCl_2

ightarrow NaCl + Cu(OH)_2$

  1. Balance Na/Cl: Add 2 to NaCl: $2NaOH(aq) + CuCl_2(aq)

ightarrow 2NaCl(aq) + Cu(OH)_2(s)$

Step3: Balance Al, F, Li, $SO_4$

For reaction c): $AlF_3(aq) + Li_2SO_4(aq)
ightarrow LiF(aq) + Al_2(SO_4)_3(s)$

  1. Balance Al: $2AlF_3 + Li_2SO_4

ightarrow LiF + Al_2(SO_4)_3$

  1. Balance $SO_4$: Add 3 to $Li_2SO_4$: $2AlF_3 + 3Li_2SO_4

ightarrow LiF + Al_2(SO_4)_3$

  1. Balance Li/F: Add 6 to LiF: $2AlF_3(aq) + 3Li_2SO_4(aq)

ightarrow 6LiF(aq) + Al_2(SO_4)_3(s)$

Step4: Balance C then H then O

For reaction d): $C_8H_{14}(l) + O_2(g)
ightarrow CO_2(g) + H_2O(g)$

  1. Balance C: $C_8H_{14} + O_2

ightarrow 8CO_2 + H_2O$

  1. Balance H: $C_8H_{14} + O_2

ightarrow 8CO_2 + 7H_2O$

  1. Balance O: Total O on right = $16 + 7 = 23$, so $O_2$ coefficient = $\frac{23}{2}$, multiply all by 2:

Final: $2C_8H_{14}(l) + 23O_2(g)
ightarrow 16CO_2(g) + 14H_2O(g)$

Brief Explanations

Each structure is drawn following IUPAC rules: identify parent chain, add substituents, place double/triple bonds at the correct position.

Answer:

a) $\boldsymbol{C_7H_{12}(l) + 10O_2(g)
ightarrow 7CO_2(g) + 6H_2O(g)}$
b) $\boldsymbol{2NaOH(aq) + CuCl_2(aq)
ightarrow 2NaCl(aq) + Cu(OH)_2(s)}$
c) $\boldsymbol{2AlF_3(aq) + 3Li_2SO_4(aq)
ightarrow 6LiF(aq) + Al_2(SO_4)_3(s)}$
d) $\boldsymbol{2C_8H_{14}(l) + 23O_2(g)
ightarrow 16CO_2(g) + 14H_2O(g)}$

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For Question 8 (Drawing Organic Structures, simplified skeletal/condensed form)