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Question
a. a ramp is designed that is 4 feet high and has a horizontal length of 50 feet. does this ramp meet the law? explain.
To determine if the ramp meets the law, we assume the law requires a maximum slope (ratio of height to horizontal length) of, say, \( \frac{1}{12} \) (a common accessibility standard).
Step 1: Calculate the slope of the ramp
The slope \( m \) of a ramp is given by the ratio of its height (\( h \)) to its horizontal length (\( l \)):
\( m = \frac{h}{l} \)
Substitute \( h = 4 \) feet and \( l = 50 \) feet:
\( m = \frac{4}{50} = \frac{2}{25} = 0.08 \)
Step 2: Compare with the standard slope
The common accessibility standard for ramps is a maximum slope of \( \frac{1}{12} \approx 0.0833 \).
Since \( 0.08 < 0.0833 \) (i.e., \( \frac{2}{25} < \frac{1}{12} \)), the slope of this ramp is less than the standard maximum slope.
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Yes, the ramp meets the law (assuming the law follows the 1:12 slope standard) because its slope (\( \frac{4}{50} = \frac{2}{25} = 0.08 \)) is less than the maximum allowed slope of \( \frac{1}{12} \approx 0.0833 \).