Question

a random sample of 10 subjects have weights with a standard deviation of 11.7642 kg. what is the variance of their weights? be sure to include the appropriate units with the result. the variance of the sample data is (round to four decimal places as needed)

Explanation:

Step1: Recall the variance - standard deviation relationship

The variance ($s^{2}$) is the square of the standard deviation ($s$).

Step2: Calculate the variance

Given $s = 11.7642$ kg. Then $s^{2}=(11.7642)^{2}$.
\[s^{2}=11.7642\times11.7642 = 138.3173\]

Answer:

$138.3173$ kg$^{2}$