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recall that the distance formula is $sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}=…

Question

recall that the distance formula is $sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}=$distance. to determine the distance between points d and l, start by dragging point c to form right triangle cdl so that the legs are parallel to the axes. there are two locations for point c that will form a right triangle. in both places where you can place point c to form horizontal distance between points d and l, $|x_2 - x_1|$. the vertical distance between points d and l, $|y_2 - y_1|$. use the distance formula to determine the distance between (-4, -9) and (11, 10). enter the squares of the vertical and horizontal distances. (-4, -9) and (11, 10) are d and l, the blocks.

Explanation:

Step1: Identify the distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Assume two points

Let's assume two points $D(x_1,y_1)$ and $L(x_2,y_2)$. From the options, if we take $D(-4,-9)$ and $L(11,10)$.

Step3: Calculate the horizontal distance

The horizontal distance is $|x_2 - x_1|=|11-(-4)| = 15$.

Step4: Calculate the vertical distance

The vertical distance is $|y_2 - y_1|=|10 - (-9)|=19$.

Step5: Calculate the distance using the formula

$d=\sqrt{(11 - (-4))^2+(10-(-9))^2}=\sqrt{(15)^2+(19)^2}=\sqrt{225 + 361}=\sqrt{586}$.

Answer:

The two - point pair for which we can calculate the distance using the distance formula as per the problem context is $(-4,-9)$ and $(11,10)$