Question

1. a rectangular block of copper metal mass 1896 g. the dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. from this data, what is the density of copper?

Explanation:

Step1: Calculate the volume of the rectangular block

The volume \( V \) of a rectangular block is given by the formula \( V = l \times w \times h \), where \( l \), \( w \), and \( h \) are the length, width, and height respectively. Here, \( l = 8.4 \, \text{cm} \), \( w = 5.5 \, \text{cm} \), and \( h = 4.6 \, \text{cm} \).
\[
V = 8.4 \times 5.5 \times 4.6
\]
First, calculate \( 8.4 \times 5.5 = 46.2 \). Then, \( 46.2 \times 4.6 = 212.52 \, \text{cm}^3 \).

Step2: Calculate the density of copper

Density \(
ho \) is defined as mass \( m \) divided by volume \( V \), i.e., \(
ho = \frac{m}{V} \). The mass \( m = 1896 \, \text{g} \) and the volume \( V = 212.52 \, \text{cm}^3 \).
\[

ho = \frac{1896}{212.52} \approx 8.92 \, \text{g/cm}^3
\]

Answer:

The density of copper is approximately \( 8.92 \, \text{g/cm}^3 \) (or more precisely, after calculation \( \frac{1896}{212.52}\approx8.92 \) \( \text{g/cm}^3 \))