QUESTION IMAGE
Question
reflect the figure over the line x = 1. plot all of the points of the reflected figure. you may click a plotted point to delete it. answer attempt 1 out of 2
Step1: Recall reflection formula
For a point $(x,y)$ reflected over the line $x = a$, the new - $x$ coordinate is $2a - x$ and the $y$ - coordinate remains the same. Here $a = 1$, so the transformation for a point $(x,y)$ is $(2\times1 - x,y)=(2 - x,y)$.
Step2: Identify original points
Let's assume the original points of the polygon are $(x_1,y_1),(x_2,y_2),(x_3,y_3),(x_4,y_4)$. For example, if one of the points is $(4,-2)$, then the reflected point is $(2 - 4,-2)=(-2,-2)$.
Step3: Apply formula to all points
Repeat the process for all the vertices of the given figure. Calculate the new $x$ - coordinate as $2 - x$ and keep the $y$ - coordinate the same for each vertex of the polygon. Then plot these new points on the coordinate - plane.
Since we don't have the exact coordinates of the original points, we can't give the exact final coordinates. But the general method for reflecting a point $(x,y)$ over the line $x = 1$ is to get the point $(2 - x,y)$.
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Step1: Recall reflection formula
For a point $(x,y)$ reflected over the line $x = a$, the new - $x$ coordinate is $2a - x$ and the $y$ - coordinate remains the same. Here $a = 1$, so the transformation for a point $(x,y)$ is $(2\times1 - x,y)=(2 - x,y)$.
Step2: Identify original points
Let's assume the original points of the polygon are $(x_1,y_1),(x_2,y_2),(x_3,y_3),(x_4,y_4)$. For example, if one of the points is $(4,-2)$, then the reflected point is $(2 - 4,-2)=(-2,-2)$.
Step3: Apply formula to all points
Repeat the process for all the vertices of the given figure. Calculate the new $x$ - coordinate as $2 - x$ and keep the $y$ - coordinate the same for each vertex of the polygon. Then plot these new points on the coordinate - plane.
Since we don't have the exact coordinates of the original points, we can't give the exact final coordinates. But the general method for reflecting a point $(x,y)$ over the line $x = 1$ is to get the point $(2 - x,y)$.