Question

reflections
if $p = (-2, 3)$ find $p$ after $r_{x=1}(p)$
$p = (?, \square)$

Explanation:

Step1: Calculate horizontal distance to line

Distance from $x=-2$ to $x=1$: $1 - (-2) = 3$

Step2: Find new x-coordinate

Add distance to line's x-value: $1 + 3 = 4$

Step3: Keep y-coordinate unchanged

Original y-coordinate is $3$, so new y is $3$.

Answer:

$P' = (4, 3)$