Question

related multiplication &
division practice problems
in each box, fill in the numbers that complete the math problems.
1
$9\div1 = \underline{\quad}$
$\underline{\quad}\times1 = 9$
2
$12\div2 = \underline{\quad}$
$\underline{\quad}\times6 = 12$
3
$\underline{\quad}\div3 = 7$
$7\times3 = \underline{\quad}$
4
$8\div\underline{\quad} = 2$
$\underline{\quad}\times2 = 8$
5
$18\div2 = \underline{\quad}$
$9\times2 = \underline{\quad}$
6
$20\div\underline{\quad} = 4$
$\underline{\quad}\times4 = 20$
7
$9\div3 = \underline{\quad}$
$\underline{\quad}\times3 = 9$
8
$10\div\underline{\quad} = 2$
$\underline{\quad}\times2 = 10$
9
$\underline{\quad}\div5 = 3$
$5\times3 = \underline{\quad}$
10
$22\div2 = \underline{\quad}$
$11\times\underline{\quad} = 22$
11
$\underline{\quad}\div9 = 4$
$9\times4 = \underline{\quad}$
12
$30\div6 = \underline{\quad}$
$\underline{\quad}\times6 = 30$

Explanation:

Problem 1

Step1: Solve \(9\div1\)

Any number divided by 1 is itself, so \(9\div1 = 9\).

Step2: Solve \(\underline{\quad}\times1 = 9\)

Any number multiplied by 1 is itself, so the number is 9.

Step1: Solve \(12\div2\)

\(12\div2 = 6\) (since \(2\times6 = 12\)).

Step2: Solve \(\underline{\quad}\times6 = 12\)

To find the missing factor, divide 12 by 6: \(12\div6 = 2\).

Step1: Solve \(\underline{\quad}\div3 = 7\)

Multiply 7 by 3: \(7\times3 = 21\), so the dividend is 21.

Step2: Solve \(7\times3\)

\(7\times3 = 21\).

Answer:

\(9\div1=\boldsymbol{9}\)
\(\boldsymbol{9}\times1 = 9\)

Problem 2