Question

remove all perfect squares from inside the square root.\\(\sqrt{112a^6}=\square\\)

Explanation:

Step1: Factor into perfect squares

$\sqrt{112a^6} = \sqrt{16 \times 7 \times (a^3)^2}$

Step2: Extract perfect square roots

$\sqrt{16} \times \sqrt{(a^3)^2} \times \sqrt{7}$

Step3: Simplify extracted terms

$4 \times a^3 \times \sqrt{7}$

Step4: Combine simplified terms

$4a^3\sqrt{7}$

Answer:

$4a^3\sqrt{7}$