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Question
to rent a certain meeting room, a college charges a reservation fee of $16 and an additional fee of $4 per hour. the chemistry club wants to spend at most $44 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room? use t for the number of hours. write your answer as an inequality solved for t.
Step1: Set up the cost - inequality
The reservation fee is $16$ and the additional fee is $4$ per hour. Let $t$ be the number of hours. The total cost $C$ is $C = 16+4t$. The club wants to spend at most $44$, so the inequality is $16 + 4t\leq44$.
Step2: Solve the inequality for $t$
Subtract 16 from both sides of the inequality: $4t\leq44 - 16$. So $4t\leq28$.
Step3: Isolate $t$
Divide both sides of the inequality by 4: $t\leq\frac{28}{4}$. So $t\leq7$.
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$t\leq7$