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repeated challenges solve as many inequalities as you have time for. wh…

Question

repeated challenges
solve as many inequalities as you have time for.
what are the solutions to this inequality?
$4x + 2 \leq 10$

Explanation:

Step1: Subtract 2 from both sides

To isolate the term with \( x \), we subtract 2 from both sides of the inequality \( 4x + 2 \leq 10 \). This gives us \( 4x + 2 - 2 \leq 10 - 2 \), which simplifies to \( 4x \leq 8 \).

Step2: Divide both sides by 4

To solve for \( x \), we divide both sides of the inequality \( 4x \leq 8 \) by 4. This gives us \( \frac{4x}{4} \leq \frac{8}{4} \), which simplifies to \( x \leq 2 \).

Answer:

\( x \leq 2 \)