Question

required informationa 5-kg block being pushed across a table by a force $p$ has an acceleration of $7\\ \text{m/s}^2$.note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.what is the net force acting on the block?the net force acting on the block is $\boldsymbol{\square}$ n.

Explanation:

Step1: Recall Newton's second law

Newton's second law states $F_{net} = m \cdot a$, where $F_{net}$ is net force, $m$ is mass, and $a$ is acceleration.

Step2: Substitute given values

Substitute $m = 5\ \text{kg}$ and $a = 7\ \text{m/s}^2$ into the formula:
$F_{net} = 5 \cdot 7$

Answer:

35