Question

review homework: unit 3 - geometry question 26, 6.4.11 hw score: 56.9%, 33 of 58 points points: 0 of 1 find the area of the given geometric figure. trapezoid with top base 9 m, bottom base 11 m, height 6 m the area of the trapezoid is (simplify your answer.)

Explanation:

Step1: Recall trapezoid area formula

The formula for the area of a trapezoid is $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the two parallel sides (bases), and $h$ is the height.

Step2: Identify values

Here, $b_1 = 9\,\text{m}$, $b_2 = 11\,\text{m}$, and $h = 6\,\text{m}$.

Step3: Substitute into formula

Substitute the values into the formula: $A = \frac{1}{2}(9 + 11) \times 6$.
First, calculate the sum of the bases: $9 + 11 = 20$.
Then, multiply by $\frac{1}{2}$ and the height: $\frac{1}{2} \times 20 \times 6 = 10 \times 6 = 60$.

Answer:

$60$ square meters