Question

1. rewrite \\(\log_{3} 9 = 2\\) in exponential form.

Explanation:

Step1: Recall the logarithmic to exponential conversion rule

The general form of a logarithm is \(\log_{b} a = c\), which can be converted to exponential form as \(b^{c}=a\), where \(b>0\), \(b
eq1\), \(a>0\).

Step2: Identify the values of \(b\), \(a\), and \(c\) from \(\log_{3} 9 = 2\)

Here, the base \(b = 3\), the result of the logarithm \(c = 2\), and the argument \(a=9\).

Step3: Apply the conversion rule

Substitute \(b = 3\), \(c = 2\), and \(a = 9\) into the exponential form \(b^{c}=a\). We get \(3^{2}=9\).

Answer:

\(3^{2}=9\)