Question

rewrite the expression in the form $k \cdot y^n$. write the exponent as an integer, fraction, or an exact decimal (not a mixed number). $3y^{\frac{-4}{3}} \cdot 2\sqrt3{y} = \square$

Explanation:

Step1: Multiply the coefficients

$3 \times 2 = 6$

Step2: Rewrite root as exponent

$\sqrt[3]{y} = y^{\frac{1}{3}}$

Step3: Add exponents of $y$

$y^{-\frac{4}{3}} \cdot y^{\frac{1}{3}} = y^{-\frac{4}{3} + \frac{1}{3}} = y^{-\frac{3}{3}} = y^{-1}$

Step4: Combine coefficient and term

$6 \cdot y^{-1}$

Answer:

$6y^{-1}$