Question

rewrite the function $f(x)=4(x-4)^2 +3$ in the form $f(x)=ax^2 +bx+c$.
$f(x)=\square$

Explanation:

Step1: Expand $(x-4)^2$

$(x-4)^2 = x^2 - 8x + 16$

Step2: Multiply by 4

$4(x^2 - 8x + 16) = 4x^2 - 32x + 64$

Step3: Add the constant term 3

$4x^2 - 32x + 64 + 3 = 4x^2 - 32x + 67$

Answer:

$f(x)=4x^2 - 32x + 67$