Question

rewrite the function $f(x)=-2(x-2)^2 + 5$ in the form $f(x)=ax^2 +bx+c$.
$f(x)=\square$

Explanation:

Step1: Expand $(x-2)^2$

$(x-2)^2 = x^2 - 4x + 4$

Step2: Multiply by -2

$-2(x^2 - 4x + 4) = -2x^2 + 8x - 8$

Step3: Add the constant term 5

$-2x^2 + 8x - 8 + 5 = -2x^2 + 8x - 3$

Answer:

$f(x) = -2x^2 + 8x - 3$