Question

rewrite \\(\frac{x + 1}{x + 1}\\) in lowest terms. \\(\frac{(x + 1)(x + 4)}{(x + 1)(x + 3)}\\)

Explanation:

Step1: Identify non-zero common factor

The common factor is $x+1$, where $x
eq -1$ (to avoid division by zero).

Step2: Cancel common factor

$\frac{(x+1)(x+4)}{(x+1)(x+3)} = \frac{x+4}{x+3}$

Step3: Simplify the initial fraction

$\frac{x+1}{x+1} = 1$, where $x
eq -1$

Answer:

For $\frac{x+1}{x+1}$: $1$ (with $x
eq -1$)
For $\frac{(x+1)(x+4)}{(x+1)(x+3)}$: $\frac{x+4}{x+3}$ (with $x
eq -1$)