Question

rewrite without parentheses.
-4y^5(-4y^2 + 7)
simplify your answer as much as possible.

Explanation:

Step1: Apply distributive property

We use the distributive property \(a(b + c)=ab+ac\), here \(a = - 4y^{5}\), \(b=-4y^{2}\), \(c = 7\). So we have \(-4y^{5}\times(-4y^{2})+(-4y^{5})\times7\)

Step2: Multiply the coefficients and add exponents for like bases

For the first term: \(-4\times(-4)y^{5 + 2}=16y^{7}\) (using the rule \(a^{m}\times a^{n}=a^{m + n}\))
For the second term: \(-4\times7y^{5}=-28y^{5}\)

Answer:

\(16y^{7}-28y^{5}\)