Question

1. a room that is 20.8 feet by 14.6 feet has a 2.4 foot - wide slate walkway around the edge of the room. the interior of the room is carpeted. what is the perimeter of the carpeted part of the room?

Explanation:

Step1: Find the length of the carpeted part

The original length is 20.8 feet. Subtract 2 times the width of the walk - way (since it's on both sides). So the length of the carpeted part $l=20.8 - 2\times2.4=20.8 - 4.8 = 16$ feet.

Step2: Find the width of the carpeted part

The original width is 14.6 feet. Subtract 2 times the width of the walk - way. So the width of the carpeted part $w=14.6 - 2\times2.4=14.6 - 4.8 = 9.8$ feet.

Step3: Calculate the perimeter of the carpeted part

The formula for the perimeter of a rectangle is $P = 2(l + w)$. Substitute $l = 16$ and $w = 9.8$ into the formula: $P=2(16 + 9.8)=2\times25.8 = 51.6$ feet.

Answer:

51.6 feet