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rope l is $\frac{1}{15}$ foot long and rope k is $\frac{1}{5}$ foot lon…

Question

rope l is $\frac{1}{15}$ foot long and rope k is $\frac{1}{5}$ foot long. how many times as long as rope k is rope l?label the tape diagram to represent the problem.rope l

Explanation:

Step1: Identify given lengths

Rope L length: $\frac{1}{15}$ foot; Rope K length: $\frac{1}{5}$ foot

Step2: Set up division for comparison

To find how many times longer Rope K is, divide Rope K's length by Rope L's length:
$\frac{\frac{1}{5}}{\frac{1}{15}}$

Step3: Simplify the division

Dividing by a fraction is multiplying by its reciprocal:
$\frac{1}{5} \times 15 = 3$

For the tape diagram:

  • Label the shorter segment (Rope L) as $\frac{1}{15}$ foot.
  • The longer segment (Rope K) should be divided into 3 equal parts, each equal to the length of Rope L, and label the entire Rope K segment as $\frac{1}{5}$ foot.

Answer:

Rope K is 3 times as long as Rope L.
Tape diagram labels:

  • Shorter segment (Rope L): $\frac{1}{15}$ ft
  • Longer segment (Rope K): $\frac{1}{5}$ ft, divided into 3 equal $\frac{1}{15}$ ft parts