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round off your answer in 2 decimal point. include direction if needed. box your final answer
find
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- what is the average speed and velocity of my bunny rabbit when she hops 6 meters to the east across the room in 11 seconds?
- what is otters speed and velocity when it takes him 2 minutes to walk 100 meters north and another 1 minute to walk 70 meters to the west?
- the boy travels to the church then to the mall. the first distance he covered is 150 m, north and the second distance is 150 m west. the boy covered the whole journey in 4 minutes.
a. what is the displacement covered by the boy?
b. find speed
c. find velocity
1.
Step1: Calculate average speed
Average speed is total distance divided by total time. Distance = 6 m, time = 11 s.
$v_{s}=\frac{d}{t}=\frac{6}{11}\approx0.55$ m/s
Step2: Calculate average velocity
Average velocity is displacement divided by time. Displacement = 6 m east, time = 11 s.
$v_{v}=\frac{\Delta x}{t}=\frac{6}{11}\approx0.55$ m/s east
Step1: Calculate total distance and total time
Total distance $d = 100 + 70=170$ m. Total time $t=2 + 1=3$ minutes = 180 s.
Step2: Calculate speed
$v_{s}=\frac{d}{t}=\frac{170}{180}\approx0.94$ m/s
Step3: Calculate displacement
Using Pythagorean theorem for displacement. $x = \sqrt{100^{2}+70^{2}}=\sqrt{10000 + 4900}=\sqrt{14900}\approx122.07$ m.
Direction $\theta=\tan^{- 1}(\frac{70}{100})\approx35.00^{\circ}$ west of north.
Step4: Calculate velocity
$v_{v}=\frac{\Delta x}{t}=\frac{122.07}{180}\approx0.68$ m/s, 35.00° west of north
Step1: Calculate displacement
Using Pythagorean theorem. Displacement $x=\sqrt{150^{2}+150^{2}}=\sqrt{2\times150^{2}} = 150\sqrt{2}\approx212.13$ m.
Direction $\theta = 45^{\circ}$ west of north.
Step2: Calculate total distance
Total distance $d=150 + 150 = 300$ m. Total time $t = 4$ minutes = 240 s.
Step3: Calculate speed
$v_{s}=\frac{d}{t}=\frac{300}{240}=1.25$ m/s
Step4: Calculate velocity
$v_{v}=\frac{\Delta x}{t}=\frac{212.13}{240}\approx0.88$ m/s, 45° west of north
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Average speed: 0.55 m/s
Average velocity: 0.55 m/s east