Question

sample a
mass of each particle: 44 u
average particle speed: 440 m/s
sample b
mass of each particle: 44 u
average particle speed: 350 m/s
compare the average kinetic energies of the particles in each sample. which sample has the higher temperature?
sample a
sample b
neither; the samples have the same temperature

Explanation:

Step1: Recall kinetic - energy formula

The formula for kinetic energy of a single particle is $K = \frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the speed.

Step2: Calculate kinetic energy for sample A

Given $m = 44u$ and $v_A=440m/s$, then $K_A=\frac{1}{2}\times44\times(440)^{2}$.

Step3: Calculate kinetic energy for sample B

Given $m = 44u$ and $v_B = 350m/s$, then $K_B=\frac{1}{2}\times44\times(350)^{2}$.
Since the mass is the same for both samples, and $440>350$, the kinetic - energy of particles in sample A is higher. Temperature is related to the average kinetic energy of particles. Higher average kinetic energy of particles means higher temperature.

Answer:

sample A