Question

scalar multiplication

1. find 3a if $a = \

$$\begin{bmatrix}2 & -4 \\\\ 0 & 5\\end{bmatrix}$$

$.

1. find

Explanation:

Step1: Multiply scalar by each element

To find $3A$, multiply each entry in matrix $A$ by 3.
$3A = 3\times

$$\begin{bmatrix}2 & -4 \\0 & 5\end{bmatrix}$$

=

$$\begin{bmatrix}3\times2 & 3\times(-4) \\3\times0 & 3\times5\end{bmatrix}$$

$

Step2: Calculate each product

Compute the value of each entry.

$$\begin{bmatrix}6 & -12 \\0 & 15\end{bmatrix}$$

Answer:

$$\begin{bmatrix}6 & -12 \\0 & 15\end{bmatrix}$$