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scatter plots: line of best fit write the slope-intercept form equation…

Question

scatter plots: line of best fit
write the slope-intercept form equation of the trend line of each scatter plot.

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

equation of the trend line:

Explanation:

Response
Problem 1 (First Scatter Plot)

Step1: Identify two points on the line

From the graph, the line passes through \((0, 9)\) (y-intercept) and let's take another point, say \((10, 6)\).

Step2: Calculate the slope (\(m\))

The slope formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Using \((0, 9)\) as \((x_1,y_1)\) and \((10, 6)\) as \((x_2,y_2)\), we get \(m=\frac{6 - 9}{10 - 0}=\frac{-3}{10}=-0.3\).

Step3: Write the slope - intercept form (\(y = mx + b\))

We know \(b = 9\) (from the y - intercept \((0,9)\)) and \(m=-0.3\). So the equation is \(y=-0.3x + 9\) or \(y =-\frac{3}{10}x+9\).

Step1: Identify two points on the line

The line passes through \((0, 10)\) (y - intercept) and \((10, 22)\).

Step2: Calculate the slope (\(m\))

Using the slope formula \(m=\frac{y_2 - y_1}{x_2 - x_1}\) with \((x_1,y_1)=(0,10)\) and \((x_2,y_2)=(10,22)\), we have \(m=\frac{22 - 10}{10 - 0}=\frac{12}{10}=1.2\) or \(\frac{6}{5}\).

Step3: Write the slope - intercept form

Since \(b = 10\) and \(m = 1.2\), the equation is \(y = 1.2x+10\) or \(y=\frac{6}{5}x + 10\).

Step1: Identify two points on the line

The line passes through \((0, 0)\) (y - intercept) and \((25, 35)\) (approximate).

Step2: Calculate the slope

\(m=\frac{35 - 0}{25 - 0}=\frac{35}{25}=\frac{7}{5}=1.4\).

Step3: Write the slope - intercept form

Since \(b = 0\) and \(m = 1.4\), the equation is \(y = 1.4x\) or \(y=\frac{7}{5}x\).

Answer:

\(y =-\frac{3}{10}x + 9\) (or \(y=-0.3x + 9\))

Problem 2 (Second Scatter Plot)