Question

2.2
score: 2/23 answered: 2/23
question 3
find the distance between the pair of points and the midpoint of the line segment joinging them.
(3, -4), (3, 4)
distance:
midpoint: (
question help: video ebook written example

Explanation:

Step1: Recall distance formula

The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here $x_1 = 3,y_1=-4,x_2 = 3,y_2 = 4$.
$d=\sqrt{(3 - 3)^2+(4-(-4))^2}$

Step2: Simplify distance formula

$d=\sqrt{0+(4 + 4)^2}=\sqrt{8^2}=8$

Step3: Recall mid - point formula

The mid - point $M$ of the line segment joining $(x_1,y_1)$ and $(x_2,y_2)$ is $M=(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$.
$M=(\frac{3+3}{2},\frac{-4 + 4}{2})$

Step4: Simplify mid - point formula

$M=(3,0)$

Answer:

Distance: $8$
Midpoint: $(3,0)$