Question

score: 0 of 1 point
find the midpoint of the line segment from (1,5) to (2,2).
a (3,7)
b ($\frac{3}{2}$,$\frac{7}{2}$)
c ($-\frac{1}{2}$,$\frac{3}{2}$)
d ($\frac{3}{2}$,$-\frac{7}{2}$)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$.

Step2: Identify the values of $x_1,y_1,x_2,y_2$

Here, $x_1 = 1,y_1 = 5,x_2 = 2,y_2 = 2$.

Step3: Calculate the x - coordinate of the mid - point

$x=\frac{1 + 2}{2}=\frac{3}{2}$.

Step4: Calculate the y - coordinate of the mid - point

$y=\frac{5+2}{2}=\frac{7}{2}$.

Answer:

B. $(\frac{3}{2},\frac{7}{2})$