Question

section 5.1 homework score: 7/17 answered: 7/17 question 8 a bag of m&ms has 3 red, 4 green, 6 blue, and 7 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places) a) a yellow? b) a blue or green? c) an orange?

Explanation:

Step1: Calculate total number of M&M's

Total = 3 (red) + 4 (green) + 6 (blue) + 7 (yellow)=20

Step2: Calculate probability of picking a yellow

Probability of yellow = $\frac{\text{Number of yellow}}{\text{Total number of M&M's}}=\frac{7}{20}= 0.35$

Step3: Calculate probability of blue or green

Number of blue or green = 6 (blue)+4 (green)=10. Probability of blue or green = $\frac{10}{20}=0.5$

Step4: Since there are no orange M&M's

Probability of orange = 0

Answer:

a) 0.35
b) 0.5
c) 0