QUESTION IMAGE
Question
select the angle(s) with measures that are less than m∠7
□ a) ∠5
□ b) ∠6
□ c) ∠2
□ d) ∠1
□ e) ∠3
□ f) ∠4
□ g) ∠tuv
To determine which angles have measures less than \( m\angle 7 \), we use the Exterior Angle Theorem and properties of triangle angles (larger side opposite larger angle, larger angle opposite larger side).
Step 1: Analyze \( \angle 7 \) (Exterior Angle)
\( \angle 7 \) is an exterior angle at \( T \) for \( \triangle UTW \). By the Exterior Angle Theorem, \( m\angle 7 = m\angle 2 + m\angle 3 \). Thus, \( m\angle 7 > m\angle 2 \) and \( m\angle 7 > m\angle 3 \).
Step 2: Analyze Sides and Opposite Angles
- In \( \triangle UTW \): Side \( UT \) (length 7) is opposite \( \angle 1 \); side \( UW \) (length 3) is opposite \( \angle 2 \); side \( TW \) (length \( 2 + 1 = 3 \)? Wait, no—wait, the segments: \( XT = 7 \), \( TW = 2 + 1 = 3 \)? Wait, no, the diagram labels: \( XT = 7 \), \( TTW \) (wait, \( T \) to \( W \) is \( 2 + 1 \)? Wait, the segments on the base: \( XT = 7 \), \( T \) to \( W \): \( 2 \) and \( 1 \), so \( TW = 2 + 1 = 3 \)? \( W \) to \( V \): \( 4 + 6 = 10 \)? Wait, no, the sides of the triangles: \( UT \) (from \( U \) to \( T \)) is length 7? Wait, no—wait, the labels: \( 7 \) is \( XT \) (a ray), \( 2 \) is \( \angle 2 \) (at \( T \), between \( XT \) and \( UT \)), \( 3 \) is \( \angle 3 \) (at \( U \), between \( UT \) and \( UW \)), \( 1 \) is \( \angle 1 \) (at \( W \), between \( UW \) and \( TW \)), \( 4 \) is \( \angle 4 \) (at \( W \), between \( UW \) and \( WV \)), \( 5 \) is \( \angle 5 \) (at \( U \), between \( UW \) and \( UV \)), \( 6 \) is \( \angle 6 \) (at \( V \), between \( UV \) and \( WV \)).
Wait, let’s re-express:
- \( \triangle UTV \): Sides: \( UT \) (opposite \( \angle 6 \)), \( UV \) (opposite \( \angle 2 + \angle 1 \)), \( TV \) (length \( 7 + 2 + 1 + 4 + 6 \)? No, the base is \( XT \) (ray) to \( T \) to \( W \) to \( V \). So \( XT = 7 \) (ray), \( T \) to \( W \): \( 2 + 1 \) (angles \( \angle 2 \) and \( \angle 1 \)), \( W \) to \( V \): \( 4 + 6 \) (angles \( \angle 4 \) and \( \angle 6 \)).
Wait, better approach: In a triangle, the larger side is opposite the larger angle.
- \( \angle 7 \) is an exterior angle, so it is greater than any non-adjacent interior angle. For \( \angle 7 \), the non-adjacent interior angles in \( \triangle UTW \) are \( \angle 2 \) and \( \angle 3 \), so \( m\angle 7 > m\angle 2 \) and \( m\angle 7 > m\angle 3 \).
- For \( \angle 5 \): In \( \triangle UWV \), side \( WV = 4 + 6 = 10 \), side \( UW = 3 \) (wait, no—\( UW \) is length 3? No, the numbers are angle labels? Wait, no, the numbers are segment lengths? Wait, the diagram has numbers next to segments: \( 7 \) (XT), \( 2 \) (angle at T), \( 3 \) (angle at U), \( 1 \) (angle at W), \( 4 \) (angle at W), \( 5 \) (angle at U), \( 6 \) (angle at V). Oh! Wait, the numbers are angle measures? No, that can’t be. Wait, the numbers are segment lengths: \( XT = 7 \), \( TW = 2 + 1 = 3 \), \( WV = 4 + 6 = 10 \), \( UT = 7 \)? No, this is confusing. Wait, the key is: \( \angle 7 \) is an exterior angle, so it is greater than \( \angle 2 \) and \( \angle 3 \) (by Exterior Angle Theorem).
Now, check other angles:
- \( \angle 5 \): In \( \triangle UWV \), side \( WV = 10 \), side \( UW = 3 \) (if \( UW = 3 \), \( UV \) is longer? No, this is unclear. Wait, the original problem is to select angles with measure less than \( m\angle 7 \). From the options: \( \angle 2 \), \( \angle 3 \), \( \angle 1 \), \( \angle 4 \), \( \angle 5 \), \( \angle 6 \), \( \angle TUV \).
Wait, let’s recall: Exterior angle \( \angle 7 \) is greater than its remote interior angles ( \( \angle 2 \) and \( \angle 3 \) ). A…
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The angles with measures less than \( m\angle 7 \) are \( \boldsymbol{\angle 2} \) and \( \boldsymbol{\angle 3} \) (and possibly others, but from the options, \( \angle 2 \) and \( \angle 3 \) are the most direct via the Exterior Angle Theorem).
(Note: If forced to choose from the given checkboxes, the correct ones are \( \angle 2 \) and \( \angle 3 \).)