Question

select the correct answer from each drop-down menu.
if a heterozygous male with the genotype ww is mated with a homozygous recessive female of genotype ww, there is a chance that of the offspring will be heterozygous.

	w	w
w	ww	ww

if the heterozygous, ww, is crossed with a homozygous dominant, ww, then the probability of having a homozygous recessive offspring is .

	w	w
w	ww	ww

Explanation:

First Drop - Down (Heterozygous Offspring Chance)

Step1: Count Offspring Genotypes

From the Punnett square for Ww (male) × ww (female), the offspring genotypes are Ww, ww, Ww, ww. So there are 4 offspring in total.

Step2: Count Heterozygous (Ww)

The number of heterozygous (Ww) offspring is 2.

Step3: Calculate Percentage

To find the percentage, use the formula $\frac{\text{Number of heterozygous}}{\text{Total number of offspring}}×100\%$. Substituting the values, we get $\frac{2}{4}×100\% = 50\%$.

Second Drop - Down (Homozygous Recessive Offspring Probability)

Step1: Analyze Punnett Square

For the cross Ww × WW, the Punnett square gives offspring genotypes WW, Ww, WW, Ww.

Step2: Check for Homozygous Recessive (ww)

There are no offspring with the genotype ww (homozygous recessive) in the Punnett square. So the probability is 0% (or 0, but in the context of the drop - down, we can infer it's 0% as there are no ww genotypes).

Answer:

First drop - down: 50%
Second drop - down: 0% (or in the context of the problem's possible options, if we assume the drop - down has 0% as an option, otherwise based on the Punnett square, the probability is 0)