Question

select the correct answer from each drop - down menu.
a pea plant with genotype pp (purple flowers) mates with a plant with the genotype pp (white flowers). the dominant allele p codes for purple flowers. the possibility that the offspring will have purple flowers is. if an offspring from this cross mates with a pp, the possibility of homozygous dominant genotype for the flowers will be

	p	p
p	pp	pp
	p	p
p	pp	pp
p	pp	pp

(the drop - down options for the first blank are 25%, 50%, 100%)

Explanation:

Step1: Analyze first cross (PP x pp)

The Punnett square shows all offspring are $Pp$. Since $P$ (purple) is dominant, all $Pp$ plants have purple flowers. Probability = $\frac{4}{4} = 100\%$.

Step2: Analyze second cross (Pp x pp)

The Punnett square shows offspring genotypes: $2$ $Pp$, $2$ $pp$. Homozygous dominant is $PP$, which does not appear. Probability = $\frac{0}{4} = 0\%$, but from context, the dropdown aligns with the first cross's purple flower probability, and the second blank refers to the Pp x pp cross's homozygous dominant chance.

Answer:

1. The possibility that the offspring will have purple flowers is 100%
2. The possibility of homozygous dominant genotype for the flowers will be 0% (not listed in the shown dropdown, but based on the Punnett square for the second cross, no offspring are homozygous dominant)