Question

select the correct answer from each drop-down menu. what effect does a decrease in the concentration of nitrogen monoxide (no) gas have on the rate of reaction in this chemical equation? 2no(g) + h₂(g) → n₂o(g) + h₂o(g) a decrease in the concentration of nitrogen monoxide dropdown between no and h₂ molecules. the rate of the forward reaction then dropdown options: stabilizes the forward reaction, increases the energy, decreases the collisions

Explanation:

Step-by-Step Explanation:

Step 1: Analyze the first dropdown (effect of [NO] decrease)

The rate of a reaction depends on the frequency of effective collisions between reactant molecules. Concentration of a reactant (like NO here) affects the number of molecules per unit volume. A decrease in [NO] means fewer NO molecules are present. So, the number of collisions between NO and H₂ molecules will decrease.

• "stabilizes the forward reaction" is incorrect because concentration change doesn't stabilize the reaction in this context.
• "increases the energy" is incorrect because concentration change doesn't directly change the energy of molecules (temperature or catalysts affect energy/activation energy).
• "decreases the collisions" is correct as fewer NO molecules lead to fewer collisions with H₂.

Step 2: Analyze the second dropdown (effect on forward reaction rate)

Since the number of collisions between reactants (NO and H₂) decreases (from step 1), the frequency of effective collisions (which determine reaction rate) also decreases. So the rate of the forward reaction will decrease.

Final Answers:

First dropdown: decreases the collisions
Second dropdown: decreases (assuming the options for the second dropdown include "decreases" — if the options were, e.g., "increases", "decreases", "stays the same", the answer is "decreases" because fewer collisions mean lower reaction rate)

For the first dropdown, the correct option is: decreases the collisions
For the second dropdown (assuming typical options), the correct option is: decreases (or whatever the option label is for "decreases" in the dropdown, e.g., if options are "increases", "decreases", "remains constant", then "decreases")

Answer:

Step-by-Step Explanation:

Step 1: Analyze the first dropdown (effect of [NO] decrease)

The rate of a reaction depends on the frequency of effective collisions between reactant molecules. Concentration of a reactant (like NO here) affects the number of molecules per unit volume. A decrease in [NO] means fewer NO molecules are present. So, the number of collisions between NO and H₂ molecules will decrease.

• "stabilizes the forward reaction" is incorrect because concentration change doesn't stabilize the reaction in this context.
• "increases the energy" is incorrect because concentration change doesn't directly change the energy of molecules (temperature or catalysts affect energy/activation energy).
• "decreases the collisions" is correct as fewer NO molecules lead to fewer collisions with H₂.

Step 2: Analyze the second dropdown (effect on forward reaction rate)

Since the number of collisions between reactants (NO and H₂) decreases (from step 1), the frequency of effective collisions (which determine reaction rate) also decreases. So the rate of the forward reaction will decrease.

Final Answers:

First dropdown: decreases the collisions
Second dropdown: decreases (assuming the options for the second dropdown include "decreases" — if the options were, e.g., "increases", "decreases", "stays the same", the answer is "decreases" because fewer collisions mean lower reaction rate)

For the first dropdown, the correct option is: decreases the collisions
For the second dropdown (assuming typical options), the correct option is: decreases (or whatever the option label is for "decreases" in the dropdown, e.g., if options are "increases", "decreases", "remains constant", then "decreases")