Question

select the correct answer. for a one - week period, three bus routes were observed. the results are shown in the table below. a bus is selected randomly. which event has the highest probability?

	bus route a	bus route b	bus route c	total
delayed	7	8	6	21
total	35	45	30	110

a. the bus is from route c and is delayed.
b. the bus is from route b and is delayed.
c. the bus is from route a and is on time.
d. the bus is from route c and is on time.

Explanation:

Step1: Calculate probability for route A and on - time

$P(\text{Route A and On - time})=\frac{28}{110}\approx0.2545$

Step2: Calculate probability for route B and delayed

$P(\text{Route B and Delayed})=\frac{8}{110}\approx0.0727$

Step3: Calculate probability for route C and on - time

$P(\text{Route C and On - time})=\frac{24}{110}\approx0.2182$

Step4: Calculate probability for route C and delayed

$P(\text{Route C and Delayed})=\frac{6}{110}\approx0.0545$
Since $0.2545$ (probability of bus from route A and on - time) is the highest among the calculated probabilities.

Answer:

A. The bus is from route A and is on - time.