Question

select the description of each substance given by each chemical formula.
one molecule of o₂ is made of
the compound al₂o₃ is made of
the compound koh is called
done

Explanation:

Since the dropdown options are not provided, I'll explain the expected answers based on chemical concepts:

For "One molecule of \( \boldsymbol{O_2} \) is made of":

\( O_2 \) is a diatomic molecule. So, one molecule of \( O_2 \) is made of 2 oxygen atoms (or "two atoms of oxygen").

For "The compound \( \boldsymbol{Al_2O_3} \) is made of":

The formula \( Al_2O_3 \) indicates the ratio of atoms. So, the compound \( Al_2O_3 \) is made of 2 aluminum atoms and 3 oxygen atoms (or "two moles of aluminum atoms and three moles of oxygen atoms" if considering moles, but at the molecular/atomic level, it's 2 Al atoms and 3 O atoms per formula unit).

For "The compound \( \boldsymbol{KOH} \) is called":

\( KOH \) is an ionic compound. \( K^+ \) is the potassium ion, \( OH^- \) is the hydroxide ion. So, \( KOH \) is called potassium hydroxide.

If you can provide the dropdown options, I can help you select the exact one.

Answer:

Since the dropdown options are not provided, I'll explain the expected answers based on chemical concepts:

For "One molecule of \( \boldsymbol{O_2} \) is made of":

\( O_2 \) is a diatomic molecule. So, one molecule of \( O_2 \) is made of 2 oxygen atoms (or "two atoms of oxygen").

For "The compound \( \boldsymbol{Al_2O_3} \) is made of":

The formula \( Al_2O_3 \) indicates the ratio of atoms. So, the compound \( Al_2O_3 \) is made of 2 aluminum atoms and 3 oxygen atoms (or "two moles of aluminum atoms and three moles of oxygen atoms" if considering moles, but at the molecular/atomic level, it's 2 Al atoms and 3 O atoms per formula unit).

For "The compound \( \boldsymbol{KOH} \) is called":

\( KOH \) is an ionic compound. \( K^+ \) is the potassium ion, \( OH^- \) is the hydroxide ion. So, \( KOH \) is called potassium hydroxide.

If you can provide the dropdown options, I can help you select the exact one.