Question

2 shaklda 3 ta yarim doira va togri burchakli uchburchak tasvirlangan. boyolgan sohaning yuzini toping (π = 3,14 deb oling).

Explanation:

Step1: Find area of right triangle

The right triangle has legs 12 cm and 16 cm. Area of triangle is $\frac{1}{2} \times base \times height$.
So, area = $\frac{1}{2} \times 12 \times 16 = 96$ $cm^2$.

Step2: Find area of two smaller semicircles

Radius of first small semicircle ($r_1$) = $\frac{12}{2} = 6$ cm. Area of its semicircle = $\frac{1}{2} \times \pi \times r_1^2 = \frac{1}{2} \times 3.14 \times 6^2 = 56.52$ $cm^2$.
Radius of second small semicircle ($r_2$) = $\frac{16}{2} = 8$ cm. Area of its semicircle = $\frac{1}{2} \times 3.14 \times 8^2 = 100.48$ $cm^2$.
Sum of areas of two small semicircles = $56.52 + 100.48 = 157$ $cm^2$.

Step3: Find area of large semicircle

Radius of large semicircle ($R$) = $\frac{20}{2} = 10$ cm. Area of large semicircle = $\frac{1}{2} \times 3.14 \times 10^2 = 157$ $cm^2$.

Step4: Calculate area of shaded region

Shaded area = (Area of two small semicircles + Area of triangle) - Area of large semicircle.
So, shaded area = $(157 + 96) - 157 = 96$ $cm^2$.

Answer:

96 $cm^2$