Question

similar triangle solving side lengths day 1

1. solve for $x$. figures are not necessarily drawn to scale.

Explanation:

Step1: Set up proportion for similar triangles

Since $\triangle EDC \sim \triangle BAC$, corresponding sides are proportional:
$\frac{ED}{AB} = \frac{EC}{BC}$
Substitute the given values: $\frac{5}{8} = \frac{x}{11.2}$

Step2: Solve for $x$ using cross-multiplication

$8x = 5 \times 11.2$
Calculate $5 \times 11.2 = 56$, so $8x = 56$
Then $x = \frac{56}{8}$

Answer:

$7$