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Question
simple probability end of lesson test
9 which of the following is the probability against drawing the ace of diamonds from a standard deck of s
89%
92%
96%
98%
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Step1: Determine total and favorable outcomes
A standard deck has 52 cards. The ace of diamonds is 1 card. So, number of unfavorable outcomes (against drawing ace of diamonds) is \(52 - 1=51\).
Step2: Calculate probability against
Probability against an event \(=\frac{\text{Number of unfavorable outcomes}}{\text{Total number of outcomes}}\). So, \(\frac{51}{52}\approx0.9808\), which is \(98\%\) (rounded to whole number percentage).
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98% (assuming the last option is 98%, as per the context of the problem about probability against drawing ace of diamonds from a 52 - card deck)