Question

simplify.
\frac{56x^{3}y^{4}}{7x^{5}y^{5}}

Explanation:

Step1: Simplify the coefficients

$\frac{56}{7} = 8$

Step2: Simplify the $x$-terms

$\frac{x^3}{x^5} = x^{3-5} = x^{-2} = \frac{1}{x^2}$

Step3: Simplify the $y$-terms

$\frac{y^4}{y^5} = y^{4-5} = y^{-1} = \frac{1}{y}$

Step4: Combine all simplified parts

$8 \times \frac{1}{x^2} \times \frac{1}{y} = \frac{8}{x^2 y}$

Answer:

$\frac{8}{x^2 y}$