Question

simplify basic cube roots
this is the only question in this section.
question
rewrite $sqrt3{16}$ in simplest form.
answer attempt 1 out of 5

Explanation:

Step1: Prime - factorize 16

$16 = 2\times2\times2\times2=2^{4}$

Step2: Rewrite cube - root

$\sqrt[3]{16}=\sqrt[3]{2^{3}\times2}$

Step3: Apply cube - root property $\sqrt[3]{ab}=\sqrt[3]{a}\times\sqrt[3]{b}$

$\sqrt[3]{2^{3}\times2}=\sqrt[3]{2^{3}}\times\sqrt[3]{2}$

Step4: Simplify $\sqrt[3]{2^{3}}$

$\sqrt[3]{2^{3}} = 2$, so $\sqrt[3]{16}=2\sqrt[3]{2}$

Answer:

$2\sqrt[3]{2}$