Question

1. simplify by cancellation, if possible. multiply.

$\frac{2}{3}cdot\frac{15}{6}=$
$1\frac{2}{3}$
$1\frac{1}{6}$
$1\frac{13}{45}$
$1\frac{5}{9}$

Explanation:

Step1: Simplify fractions by cancellation

Cancel common factors. 2 and 6 have a common - factor of 2, and 3 and 15 have a common - factor of 3. $\frac{2}{3}\times\frac{15}{6}=\frac{2\div2}{3}\times\frac{15}{6\div2}=\frac{1}{3}\times\frac{15}{3}$. Then, since 3 and 15 have a common factor of 3, we get $\frac{1}{3\div3}\times\frac{15\div3}{3}=\frac{1}{1}\times\frac{5}{3}$.

Step2: Multiply the simplified fractions

$\frac{1}{1}\times\frac{5}{3}=\frac{1\times5}{1\times3}=\frac{5}{3}$.

Step3: Convert to mixed - number

$\frac{5}{3}=1\frac{2}{3}$

Answer:

$1\frac{2}{3}$