Question

simplify. express your answer using
$(10v^{-7})(4v)(3v^{4})$

Explanation:

Step1: Multiply coefficients

$10 \times 4 = 40$

Step2: Combine $v$ terms (add exponents)

$v^{-3} \times v^{1} = v^{-3+1} = v^{-2}$

Step3: Rewrite negative exponent

$v^{-2} = \frac{1}{v^2}$

Step4: Combine results

$40 \times \frac{1}{v^2} = \frac{40}{v^2}$

Answer:

$\frac{40}{v^2}$