Question

simplify the expression.
\\(\frac{3x^2}{6x + x^2}\\)
\\(\circ\\) a) \\(\frac{3x^2}{6 + x}\\)
\\(\circ\\) b) \\(\frac{3x}{6 + x}\\)
\\(\circ\\) c) \\(\frac{3x}{6 + x^2}\\)
\\(\circ\\) d) \\(\frac{x}{3 + x}\\)
\\(\circ\\) e) \\(\frac{x^2}{3 + x}\\)

Explanation:

Step1: Factor the denominator

Factor out \(x\) from the denominator \(6x + x^2\), we get \(x(6 + x)\). So the expression becomes \(\frac{3x^2}{x(6 + x)}\).

Step2: Cancel out the common factor

Cancel out the common factor \(x\) (assuming \(x
eq0\)) from the numerator and the denominator. The numerator \(3x^2\) divided by \(x\) is \(3x\), and the denominator \(x(6 + x)\) divided by \(x\) is \(6 + x\). So the simplified expression is \(\frac{3x}{6 + x}\).

Answer:

b) \(\frac{3x}{6 + x}\)