Question

simplify.
$(w^{-2})^{5}$
write your answer without using negative exponents.

Explanation:

Step1: Apply power of a power rule

$(w^{-2})^5 = w^{-2 \times 5}$

Step2: Calculate the exponent

$w^{-2 \times 5} = w^{-10}$

Step3: Eliminate negative exponent

$w^{-10} = \frac{1}{w^{10}}$

Answer:

$\frac{1}{w^{10}}$