Question

since molarity is defined by the equation $m=\frac{mol_{solute}}{l_{solution}}$, one must solve for moles of $nac_{2}h_{3}o_{2}$ from the given mass. how many moles are in 12.8g of $nac_{2}h_{3}o_{2}$? (hint: the molecular weight of $nac_{2}h_{3}o_{2}$ is 82.03 g/mol)
0.1560 mol
1050 mol
0.156 mol
1050 mol
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Explanation:

Step1: Recall mole - mass formula

The formula to calculate moles $n$ from mass $m$ and molar mass $M$ is $n=\frac{m}{M}$.

Step2: Substitute given values

Given $m = 12.8g$ and $M=82.03g/mol$, then $n=\frac{12.8g}{82.03g/mol}\approx0.156mol$.

Answer:

C. 0.156 mol